CROCHETTOP SWEETIE
DESIGN: MARTINA TABORSKY
www.fashionmartina.cz
FINISHED SIZE : 36/38 (40/42), t. m. bust 86-90 cm (90 - 96 cm) - the finished garment is stretchy, so it could be a litle more YARN: 5 (6) balls of $100\%$ mercerized cotton 136 yd/125 m/50 g - the original one is Catania from Schachenmayer, hook Nr. 3 STRUCTURAL PATTERN: $13+1$ stitches, the 1. - 4. row repeat 1 x, and then always repeat the 3. and 4. row. 1. row: ch 1, sc in the second ch from the hook, sc across 2. row: ch 3 (count as the first dc),turn, 2 dc in next 2 st, ch 3, skip 2 st, sc in the next st, 5 dc in the next st, sc in the next sc, skip 2 st, 3 dc in next 3 st 3. row: ch 2 (count as the first back post dc), turn, 2 back post dc in the next 2 dc, ch 3, sc in the third of dc of the previous row, ch 3, 3 back post dc in next 3 dc of the previous row 4. row: ch 3 (count as the first dc),turn, 2 dc in the next 2 dc, ch 3, sc in the third ch, 5 dc in sc, sc in the first ch, ch 3, 3 dc in the next 3 dc GAUGE FOR STRUCTURAL PATTERN: 23 stitcheS and $12\;\mathsf{r o w s}=10\times10\;\mathsf{c m}$
BASIC PATTERN: dc
GAUGE FOR BASIC PATTERN: 20 stitcheS and $13,5\;\mathsf{r o w s}=10\times10\;\mathsf{c m}$ THIS TOP COULD BE VERY SIMPLY AND EASILY MODIFIED IN THE SIZE - IF YOUADD OR REDUCE 2 PATTERN REPEATS $\mathbf{\varepsilon}=26$ STITCHESAND IFYOU WISH TO HAVE THE TOP LONGER, THEN YOU HAVE TO MAKE LONGER THE UPPER PARTIN STRUCTURAL PATTERN.
THE TOP IS WORKED TILL ARMHOLES IN ONE PIECE IN ROUNDS; THEN IT ISDIVIDED AND FRONT AND BACK IS WORKED SEPARATELY.
BACK $\mathbf{+}$ FRONT: Cast on on 182/208 ch and taking care not to twist sts., join sl st in first ch to form a ring. Then work the structural pattern $=14$ repeats of the pattern till the piece is 20 / 22 cm long. Then we continue in basic pattern $=\mathsf{d c}$ across and in the first row of the basic pattern we reduce ${28\:/\:32}$ stitches $=d c$ in every dc and sc of the previous row and 2 dc in every ch-3 space of the previous $\mathsf{r o w}=154\,/\,176\,\mathsf{d c}$ ， Continue in basic pattern til the piece ist 32/35 cm long and then separate the work in 2 pieces $=$ front and back $=$ 77 / 88 dc. From now we work in normal rows with turning of the work.
Shape armholes:
1. row: ch 1, turn, sl st in first 6 sts, ch 3, dc in each st across to the last 6 st, leave this rem 6 st unworked 2. row: ch 1, turn, sl. st in first 3 sts, ch 3, , dc in each st across to the last 3 st, leave this rem 3 st unworked 3. row: ch 1, turn, sl. st in first 2 sts, ch 3, , dc in each st across to the last 2 st, leave this rem 2 st unworked 4. row: ch 1,turn, sl. st in first 2 sts, ch3, dc in each st across to the last 2 st, leave this rem 2 st unworked 5. row, rem 3 dc, fasten off. Shape neck: in the same moment, when we begin to shape the armholes, we begin also to shape the neck: 1. row: ds in each st across, leave the middle 20 / 36 st unworked 2. row: ch 1, turn, sl st in first 6 sts, ch 3, dc in each st across to the last 6 st, leave this rem 6 st unworked 3. row: ch 1, turn, sl. st in first 3 sts, ch 3, , dc in each st across to the last 3 st, leave this rem 3 st unworked 4. row: ch 1, turn, sl. st in first 2 sts, ch 3, , dc in each st across to the last 2 st, leave this rem 2 st unworked 5. row: ch 1, turn, sl. st in first 2 sts, ch 3, , dc in each st across to the last 2 st, leave this rem 2 st unworked The second part of the back make in the same way and then make the front in the samewayas the STRAPS:MAKE $\pmb{2}\times$ : ch 71 and dc in the third ch from the hook , \*ch 1, skip 1 ch, 2 dc in next 2 st \* from \* till \* always repeat and end with ch 1, 2 dc, fasten off. FINISHING: sew the straps on the front and on the back. Across the armholes make 1 row sc and 1 row reverse sc. Across the whole neck and both straps make 1 row sc and 1 row of cluster: 1 sc in sc of the previous row, skip 2 st, 5 dc in the next sc, skip 2 sc of the previous row - repeats across the whole neck and both straps. Weave in loose ends. If you wish, you can decorate the front with some crochet flowers.
$\begin{array}{l}{{\sf R O}={\bf c h}}\\ {~~}\\ {\kappa{\sf S}={\bf s c}}\\ {~~}\\ {{\sf D S}={\bf d c}}\end{array}$ RS $=$ back posted dc
